A PHP Error was encountered

Severity: Warning

Message: Missing argument 1 for Video::view()

Filename: controllers/video.php

Line Number: 14

A PHP Error was encountered

Severity: Notice

Message: Undefined variable: video_id

Filename: controllers/video.php

Line Number: 15

A Database Error Occurred

Error Number: 1064

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1

SELECT * FROM video, channel WHERE (video.type="public" OR video.VID IN(8260,8314,8330,8701)) AND channel.id=video.channel AND video.VID=